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7n^2-65n=-72
We move all terms to the left:
7n^2-65n-(-72)=0
We add all the numbers together, and all the variables
7n^2-65n+72=0
a = 7; b = -65; c = +72;
Δ = b2-4ac
Δ = -652-4·7·72
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-47}{2*7}=\frac{18}{14} =1+2/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+47}{2*7}=\frac{112}{14} =8 $
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